We want to build a 500 MW steam power plant. The condensers will be cooled with river water. The maximum steam temperature is 540 degree C. The pressure of the Condenser will be 11 kPa. You are asked to estimate the temperature rise of the river.
Author will mail a prize to the first correct answer received before Saturday 4/28/18. The correct answer must be emailed to my email kbig104.3@gmail.com
Similar question was found in The Thermodynamics Textbook by Van Wylen and Sontag
Solution:
Wnet = 500 MW * 1,000 kW / MW * 3,412 Btu /kW hr = 1.7 * 10 ^ 9 Btu / kWhr
Th = 1,004 F = 1,464 R
Tl = 101 F = 561 R
Eff th max = Wnet / Qh = (Th - Tl ) / Th = 903 / 1460 = 0.62
Therefore :
Ql = Wnet * (1-Eff th)/Eff th = 1.7 * 10^9 (0.38/0.62) = 1.04*10^9 Btu/hr
m dot H2O = 60 m * 8 m * 10 m/min * 1000 kg/ m^3 * 60 min / hr * 2.2 lb / kg=
m dot H2O = 5.8 * 10^10 lb/hr
Delta T H2O = Ql / [(m dot H2O) * Cp H20) = 1.04*10^9 / 5.8 * 10^10 = 0.017 F
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